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Let f(n)=1+1/2+1/3++1/ndot Then f(1)+f(2...

Let `f(n)=1+1/2+1/3++1/ndot` Then `f(1)+f(2)+f(3)++f(n)` is equal to
(a)`nf(n)-1`
(b) `(n+1)f(n)-n`
(c)`(n+1)f(n)+n`
(d) `nf(n)+n`

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