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If lim(x rarr 0)[1+x ln(1+b^2)]^(1/x)=2b...

If `lim_(x rarr 0)[1+x ln(1+b^2)]^(1/x)=2b sin^2 theta, b gt 0 "and" theta in (-pi, pi]`. then the value of `theta` is

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CENGAGE PUBLICATION-LIMITS AND DERIVATIVES-All Questions
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