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Let omega=-1/2+i(sqrt(3))/2dot Then the ...

Let `omega=-1/2+i(sqrt(3))/2dot` Then the value of the determinant `|1 1 1 1-1-omega^2omega^2 1omega^2omega^4|` is `3omega` b. `3omega(omega-1)` c. `3omega^2` d. `3omega(1-omega)`

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Let omega=-1/2+i(sqrt(3))/2 . Then the value of the determinant |(1,1,1),(1,-1-omega^2,omega^2),(1,omega^2,omega^4)| is (A) 3omega (B) 3omega(omega-1) (C) 3omega^2 (D) 3omega(1-omega)

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If omega is an imaginary cube root of unity, then the value of the determinant |(1+omega,omega^(2),-omega),(1+omega^(2),omega,-omega^(2)),(omega+omega^(2),omega,-omega^(2))| is

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If omega is a cube root of unity, then find the value of the following: (1-omega)(1-omega^2)(1-omega^4)(1-omega^8)

If omega is an imaginary cube root of unit,then the value of the expression (1+1/omega)(1+1/omega^2)+(2+1/omega)(2+1/omega^2)+(3+1/omega)(3+1/omega^2) +...+ (n+1/omega)(n+1/omega^2) is

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CENGAGE PUBLICATION-COMPLEX NUMBERS AND QUADRATIC EQUATIONS-All Questions
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