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Let alpha,beta be the roots of the equat...

Let `alpha,beta` be the roots of the equation `(x-a)(x-b)=c ,c!=0.` Then the roots of the equation `(x-alpha)(x-beta)+c=0` are `a , c` b. `b , c` c. `a , b` d. `a+c , b+c`

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Since `alpha, beta` are the roots fo
`(x-a)(x-b)=c`
or `(x-a)(x-b)-c=0`
Then `(x-a)(x-b)-c-(x-alpha)(x-beta)`
`implies(x-alpha)(x-beta)+c=(x-a)(x-b)`
Hence roots of `(x-alpha)(x-beta)+c=0` are a,b.
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