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If x is real and (x^2+2x+c)/(x^2+4x+3c) ...

If `x` is real and `(x^2+2x+c)/(x^2+4x+3c)` can take all real values, of then show that `0lt=clt=1.`

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CENGAGE PUBLICATION-COMPLEX NUMBERS AND QUADRATIC EQUATIONS-All Questions
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