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Let f(x)=|[x^3,sinx,cosx],[6,-1, 0],[p,...

Let `f(x)=|[x^3,sinx,cosx],[6,-1, 0],[p, p^2,p^3]|`, where `p` is a constant. Then `(d^3)/(dx^3)(f(x))` at `x=0` is
(a)`p` (b) `p-p^3` (c)`p+p^3` (d) independent of `p`

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