A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of `1, 2, 3, 4, 5, 6, 7, 8, 9.` The number of ways in which this can be done is (a) `9!` (b) `2(7!)` (c) `4(7!)` (d) non of these

A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4, & 5 without repetition . if the total number of ways in which this can be done is n^3 , then (n!)/144 must be...

A five digit number divisible by 3 has to formed using the numerals 0,1,2,3,4,5 without repetition the total number of ways in which this can

A 5-digit number is divisible by 3 and it is formed by using 0, 1, 2, 3, 4, and 5 without repetition. Find the total number of ways in which such a number can be formed ?

The number of five-digit numbers which are divisible by 3 that can be formed by using the digits 1,2,3,4,5,6,7,8 and 9 , when repetition of digits is allowed, is (a) 3^(10) (b) 4.3^(8) (c) 5.3^(8) (d) 7.3^(8)

How many four-digit numbers can be formed by using the digits 1, 2, 3, 4, 5, 6, 7 if at least one digit is repeated.

A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

Number of 4 digit numbers which are divisible by 4 that can be formed from the digits 1,2,3,4 and 5 is

The number of distinct natural numbers up to a maximum of four digits and divisible by 5, which can be formed with the digits 0, 1 , 2, 3, 4, 5, 6, 7, 8, 9 each digit not occurring more than once in each number, is a. 1246 b. 952 c. 1106 d. none of these

Find the numbers less than 1000 and divisible by 5 which can be formed with the digits 0,1,2,3,4,5,6,7,8,9 each digit not occurring more than once in each number .

Find the three-digit odd numbers that can be formed by using the digits 1, 2, 3, 4, 5, 6 when the repetition is allowed.