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f^(prime)(x)=phi(x) and phi^(prime)(x)=f...

`f^(prime)(x)=phi(x)` and `phi^(prime)(x)=f(x)` for all x. Also,`f(3)=5` and `f^(prime)(3)=4`. Then the value of `[f(10)]^2-[phi(10)]^2` is _____

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