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Ten persons amongst whom are A,B and C are to speak at a function the number of ways in which it can be done if A wants to speak before B and B wants to speak before C is

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CENGAGE PUBLICATION-PERMUTATIONS AND COMBINATIONS-All Questions
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  2. Consider a 6xx6 chessboard. Then match the following columns. Column I...

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  3. Ten persons amongst whom are A,B and C are to speak at a function the ...

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  4. In how many ways can three persons, each throwing a single dice once, ...

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  5. In how many ways can a team of 11 players be formed out of 25 playe...

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  6. Find the number of positive integral solutions of the inequality 3x+y+...

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  7. How many integers between 1 and 10,00,000 have the sum of the digits e...

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  8. Statement 1: Number of terms in the expansion of (x+y+z+w)^(50) is ""^...

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  9. Find the number of seven letter words that can be formed by using the ...

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  10. The number of ways in which 10 candidates A1,A2, A(10) can be rank...

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  11. There are six teachers. Out of them two are primary teacher, two are ...

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  12. In the decimal system of numeration of six-digit numbers in which t...

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  13. There are 2 identical white balls, 3 identical red balls, and 4 green ...

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  14. To fill 12 vacancies, there are 25 candidates of which 5 are from sc...

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  15. Find the number of ways in which 6 boys and 6 girls can be seated in a...

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  16. If the difference of the number of arrangements of three things fro...

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  17. The number of ways in which the letters of the word ARRANGE be arrange...

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  18. The sum of all four-digit numbers that can be formed by using the d...

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  19. Find the value (s) of r satisfying the equation "^69 C(3r-1)-^(69)C(r...

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  20. The number of ordered pairs of integers (x ,y) satisfying the e...

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