If `H_n=1+1/2+...+1/ndot` , then the value of `S_n=1+3/2+5/3+...+(99)/(50)` is a. `H_(50)+50` b. `100-H_(50)` c. `49+H_(50)` d. `H_(50)+100`

Determine the volume strength of 1.5 (N) H_(2)O_(2) .

The value of 99^(50) - 99.98^(50) + (99*98)/(1*2) (97)^(50) -…+ 99 is

Show that 101^(50)gt 99^(50)+100^(50)

If the points(-1,3), (2,h) and (5,-1) are collinear, then the value of h is

The value of sum_(r=1)^(49)(2r^(2) - 48r +1)/((50-r).""^(50)C_(r)) is "_____" .

If x_1gt0,i=1,2.....50 and x_1+x_2+.....x_50=50 then the minimum value of 1/x_1+1/x_2+......1/x_50 equals to.

Which is larger : (99^(50)+100^(50)) or (101)^(50) .

Let A_(1), A_(2), A_(3), A_(4) be the areas of the triangular faces of a tetrahedron, and h_(1), h_(2), h_(3), h_(4) be the corresponding altitudes of the tetrahedron. If the volume of tetrahedron is 1//6 cubic units, then find the minimum value of (A_(1) +A_(2) + A_(3) + A_(4))(h_(1)+ h_(2)+h_(3)+h_(4)) (in cubic units).

If t_n denotes the nth term of the series 2+3+6+11+18+... then t_(50) a. 49^2-1 b. 49^2 c. 50^2+1 d. 49^2+2