Find the total number of integers 'n' such that `2 le n le 2000 ` and H.C.F of n and 36 is 1.

Find the total number of integer n such that 2lt=nlt=2000 and H.C.F. of n and 36 is 1.

When n is an odd integer, then the total number of terms in the expresion of sin n theta in powers of sin theta is-

2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all whole number such that 0 le m le 10, 0 le n le 8 and 0 le p le 7 . also, (2^0 + 2^1 +.........+2^10)(3^0 + 3^1 +.......+3^8)(5^0+5^1+....+5^7) = sum of all the divisors of 2^10 cdot 3^8 cdot 5^7 The number of proper divisors of 16200 is

If n_1 and n_2 are five-digit numbers, find the total number of ways of forming n_1 and n_2 so that these numbers can be added without carrying at any stage.

2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all whole number such that 0 le m le 10, 0 le n le 8 and 0 le p le 7 . also, (2^0 + 2^1 +.........+2^10)(3^0 + 3^1 +.......+3^8)(5^0+5^1+....+5^7) = sum of all the divisors of 2^10 cdot 3^8 cdot 5^7 The sum of odd divisors (ne 1) of 10800 is

The total number of binary operations on the set S={1,2} having 1 as the identity element is n . Find n .

Find the least positive integer n such that ((2i)/(1+i))^n is a positive integer.

Find the total number of n -digit number (n >1) having property that no two consecutive digits are same.

The number of ordered pairs of positive integers (m,n) satisfying m le 2n le 60 , n le 2m le 60 is

Let f be a function from the set of positive integers to the set of real number i.e f : N rarr R , such that f(1) + 2f{2} + 3f{3} + ….. + nf{n} = n(n + 1) f(n) for n ge 2 Then the of 1/f(4) must be