There are `4n + 1` terms in a sequence of which first `2n + 1` are in Arithmetic Progression and last `2n + 1` are in Geometric Progression the common difference of Arithmetic Progression is `2` and common ratio of Geometric Progression is `1/2`. The middle term of the Arithmetic Progression is equal to middle term of Geometric Progression. Let middle term of the sequence is `T_m` and `T_m` is the sum of infinite Geometric Progression whose sum of first two terms is `(5/4)^2 n` and ratio of these terms is `9/16`.

1. Number of terms in the given sequence is equal to -
(a) 9
(b) 17
(c) 13
(d) none

2. Middle term of the given sequence, i.e. `T_m` is equal to
(a) 16/7
(b) 32/7
(c) 48/7
(d) 16/9

3. First term of given sequence is equal to -
(a) –8/7, –20/7
(b) –36/7
(c) 36/7
(d) 48/7