Find the number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if atleast 1 green and 1 blue ball is to be included.

Explanation

At least, one green ball can be selected out of 5 green balls in `2^(5)-1`, i.e., in 31 ways.
Similarly, at least one blue ball can be selected from 4 blue balls in `2^(4)-1=15` ways. And at least one red or no red ball can be selected in `2^(3)=8` ways.
Hence, the required number of ways is `31xx15xx8=3720`.