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If the radius of a sphere is measured as...

If the radius of a sphere is measured as 9cm with an error of 0.03 cm, then find the approximate error in calculating its volume.

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r=9
`deltar`=0.03
we know,
`v=4/3pir^3`
differentiate with respec to r
`(deltav)/(deltar)=delta/(deltar)(4/3pir^3)`
`deltav=4pir^2 deltar`
`deltav= 4 (3.14)(9^2)(0.03)`
...
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