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Let `x` be the length of one of the equal sides of an isosceles triangle, and let `theta` be the angle between them. If `x` is increasing at the rate (1/12) m/h, and `theta` is increasing at the rate of `pi/(180)` radius/h, then find the rate in `m^2` / `h` at which the area of the triangle is increasing when `x=12m a n d theta=pi//4.`

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