Find the equations of the tangents drawn to the curve `y^2-2x^3-4y+8=0` from the point `(1,\ 2)` .

Explanation

y-2=slope(x-1)

`4-2-8+8!=0`

Lets say y=mx+c

`(mx+c)^2-2x^2-4y+8=0`

`(m^2-2)x^2+(2mc-4m)x+(c^2-4c+8)=0`

`D=0=b^2-4ac`

`(2mc-4m)^2-4(m^2-2)(c^2-4c+8)=0`

`c=2pmsqrt(2m^2-4`

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