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If (2, 3, 5) is one end of a diameter...

If (2, 3, 5) is one end of a diameter of the sphere `x^2+""y^2+""z^2-6x-12 y-2z""+""20""=""0` , then the coordinates of the other end of the diameter are (1) `(4,""9,-3)` (2) `(4,-3,""3)` (3) `(4,""3,""5)` (4) `(4,""3,-3)`

A

`(4,""9,-3)`

B

`(4,""3,""5)`

C

`(4,""3,-3)`

D

`(4,-3,""9)`

Text Solution

Verified by Experts

center of circle`=(6/2,12/2,2/2)`
`=(3,6,1)`
`(x+2)/2=3,(y+3)/2=6,(z+5)/2=1`
`x=4,y=9,z=-3`
option`1`
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