The distance between the origin and the normal to the curve `y=e^(2x)+x^2` at the point x = 0

The slope of the normal to the curve y= (2x)/(1+ x^(2)) at y=1 is-

At any point on the curve 2x^2y^2-x^4=c , the mean proportional between the abscissa and the difference between the abscissa and the sub-normal drawn to the curve at the same point is equal to (a) ordinate (b) radius vector (c) x-intercept of tangent (d) sub-tangent

The slope of the normal to the curve y = 2x^(2) + 3 sin x at x = 0 is

Find the equation of the normal to the curve y=|x^2-|x||a t x=-2.

The distance between the points (x,-y) and (-x,y) is

The normal to the curve x^(2) = 4y passing (1,2) is

The tangent drawn at the point (0, 1) on the curve y=e^(2x) meets the x-axis at the point -

Equation of normal to curve y=x^(3)-2x+4 at point (1,3).

Find the equation of the normal to the curve y=(1+x)^y+sin^(-1)(sin^2x) at x=0.

Find the equations of the tangent and normal to the curve y=x^2-4x-5 at x= -2.