The slope of the tangent to the curve `y=sqrt(4-x^2)` at the point where the ordinate and the abscissa are equal is `(a) -1` (b) 1 (c) 0 (d) none of these

The slope of the tangent to the curve y=2sqrt2x

The slope of the tangent to the curve (y-x^5)^2=x(1+x^2)^2 at the point (1,3) is

Find the slope of tangent of the curve 3x^3+2x+y=0 at the point (1,-1)

The slope of the tangent to the curve (y-x^(5))^(2)=x(1+x^(2))^(2) at the point (1, 3) is

Find the slope of the tangent to curve y = x^(3) – x + 1 at the point whose x-coordinate is 2.

The slope of the tangent to the curve x= 3t^(2) +1 , y=t^(3)-1 at x=1 is-

Find the slope of the tangent to the curve y= (x-1)/(x-2), x ne 2 at x = 10.

Find the length of the tangent for the curve y=x^3+3x^2+4x-1 at point x=0.

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is (a)x/a-y/b=1 (b) a x+b y=1 (c)a x-b y=1 (d) x/a+y/b=1

A curve y=f(x) passes through point P(1,1) . The normal to the curve at P is a (y-1)+(x-1)=0 . If the slope of the tangent at any point on the curve is proportional to the ordinate of the point, then the equation of the curve is (a) ( b ) (c) y=( d ) e^(( e ) (f) K(( g ) (h) x-1( i ))( j ))( k ) (l) (m) (b) ( n ) (o) y=( p ) e^(( q ) (r) K e (s))( t ) (u) (v) (c) ( d ) (e) y=( f ) e^(( g ) (h) K(( i ) (j) x-2( k ))( l ))( m ) (n) (o) (d) None of these