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If for `z` as real or complex, `(1+z^2+z^4)^8=C_0+C_1z^2+C_2z^4+...+C_(16)z^(32) then ` prove that `C_(0) - C_(1) + C_(2) - C_(3) + "….." + C_(16) = 1` and `C_(0) + C_(3) + C_(6) + C_(12) + C_(15) = 3^(7)`

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