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f(x)={4x-x^3+ln(a^2-3a+3),0lt=x<3 x-18...

`f(x)={4x-x^3+ln(a^2-3a+3),0lt=x<3`
`x-18 ,xgeq3` complete set of values of `a` such that `f(x)` as a local minima at `x=3` is
`(a) [-1,2]`
`(b) (-oo,1)uu(2,oo)`
`(c) [1,2]`
(d) `(-oo,-1)uu(2,oo)`

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