The global maximum value of `f(x)=(log)_(10)(4x^3-12 x^2+11 x-3),x in [2,3],` is `-3/2(log)_(10)3` (b) `1+(log)_(10)3` c) `(log)_(10)3` (d) `3/2(log)_(10)3`

The domain of the function f(x)=(log)_(3+x)(x^2-1) is

Solve (log)_2(3x-2)=(log)_(1/2)x

f(x)=log(x^3) ,f'(x)=?

Prove that 1/3<(log)_(10)3<1/2dot

Which of the following pairs of expression are defined for the same set of values of x ? f_1(x)=2(log)_2xa n df_2(x)=(log)_(10)x^2 f_1(x)=(log)x_xx^2a n df_2(x)=2 f_1(x)=(log)_(10)(x-2)+(log)_(10)(x-3)a n df_(2(x))=(log)_(10)(x-2)(x-3)dot

Solve (x^(log_(10)3))^(2) - (3^(log_(10)x)) - 2 = 0 .

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)

Find the domain of the function : f(x)=3/(4-x^2)+(log)_(10)(x^3-x)

Solve |x-1|^((log_(10) x)^2-log_(10) x^2=|x-1|^3

Solve (log)_4 8+(log)_4(x+3)-(log)_4(x-1)=2.