If `f(x)=(x^2-1)/(x^2+1)` . For every real number `x ,` then the minimum value of `fdot` (a) does not exist because `f` is unbounded (b) is not attained even through `f` is bounded (c) is equal to 1 (d) is equal to `-1`

The minimum value of f(x)=2x^(2)+x-1 is-

The minimum value of the function f(x)=2|x-1|+|x-2| is -

The minimum value of the function f(x)=2|x-1|+|x-2| is

If f(x)=ax^(2)+bx+c and f(x + 1) = f(x) + x + 1, then determine the values of a and b.

The minimum value of f(x)=abs(x-1)+abs(x-2)+abs(x-3) is equal to

If f(x)=3x-5, then f^(-1)(x) is given by (a) 1/((3x-5)) (b) ((x+5))/3 (c)does not exist because f is not one-one (d)does not exist because f is not onto

Consider the function f:(-oo,oo)to(-oo,oo) defined by f(x)=(x^2-a)/(x^2+a),a >0, which of the following is not true?(a) maximum value of f is not attained even though f is bounded. (b) f(x) is increasing on (0,oo) and has minimum at x=0 (c) f(x) is decreasing on (-oo,0) and has minimum at x=0. (d) f(x) is increasing on (-oo,oo) and has neither a local maximum nor a local minimum at x=0.

The real number x when added to its inverse given the minimum value of the sum at x equal to (a) 1 (b) -1 (c) -2 (d) 2

If f(x)=ax^(2)+bx+c and f(x - 1) = f(x) + 2x + 1. then find the values of a and b.

Let f(x)=(1+b^2)x^2+2b x+1 and let m(b) the minimum value of f(x) as b varies, the range of m(b) is (A) [0,1] (B) (0,1/2] (C) [1/2,1] (D) (0,1]