`Aa n dB` play a series of games which cannot be drawn and `p , q` are their respective chance of winning a single game. What is the chance that `A` wins `m` games before `B` wins `n` games?

If the probability of winning a game is 0.3, what is the probability of loosing it ?

Four persons A, B, C and D throw an unbiased die, turn by turn, in succession till one gets an even number and win the game. What is the probability that A wins the game if A begins ?

A and B throw a die alternatively till one of them gets a '6' and wins the game. Find their respective probabilities of winning, if A starts first.

A person buys a lottery ticket in 50 lotteres, in each of which his chance of winning a prize is (1)/(100) . What is the probability that he will win a prize at least once?

A person buys a lottery ticket in 50 lotteres, in each of which his chance of winning a prize is (1)/(100) . What is the probability that he will win a prize at least twice?

A person buys a lottery ticket in 50 lotteres, in each of which his chance of winning a prize is (1)/(100) . What is the probability that he will win a prize exactly once?

Two players A and B toss a die alternately he who first throws a six wins the game if A begins what is the probability that he wins? What is the probability of B winning the game?

Two players P_1a n dP_2 play a series of 2n games. Each game can result in either a win or a loss for P_1dot the total number of ways in which P_1 can win the series of these games is equal to a. 1/2(2^(2n)-.^(2n)C_n) b. 1/2(2^(2n)-2xx.^(2n)C_n) c. 1/2(2^n-.^(2n)C_n) d. 1/2(2^n-2xx.^(2n)C_n)

Forty team play a tournament. Each team plays every other team just once. Each game results in a win for one team. If each team has a 50% chance of winning each game, the probability that the end of the tournament, every team has won a different number of games is a. 1//780 b. 40 !//2^(780) c. 40 !//2^(780) d. none of these

A and B play alternately with an unbiased die. He who first throws a 'six' wins. If A begins, show that his chance of winning is (6)/(11) .