The area bounded by the x-axis, the curve `y=f(x),` and the lines `x=1,x=b` is equal to `sqrt(b^2+1)-sqrt(2)` for all `b >1,` then `f(x)` is

If the area bounded by the x-axis, the curve y=f(x), (f(x)gt0)" and the lines "x=1, x=b " is equal to "sqrt(b^(2)+1)-sqrt(2)" for all "bgt1, then find f(x).

Find the area bounded by the curve y=4x(x-1)(x-2) and the x-axis.

Find the area bounded by the curve f(x) =4-|x| and the x axis

The area bounded by the coordinate axes and the curve sqrt(x) + sqrt(y)=1 is equal to-

Find the area bounded by the curve y=x(x-1)^(2) , the y-axis and the line y=2.

The area bounded by the curve y = x^(3) , x-axis and the ordinates: x = - 1 and x= 1 is given by

If the area bounded by the curve y=f(x), x-axis and the ordinates x=1 and x=b is (b-1) sin (3b+4), then find f(x).

Area bounded by the curve y=x^(3) , the x-axis and the ordinates x = -2 and x = 1 is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4a n dx=beta>pi/4i sbetasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is (pi/2-sqrt(2)-1) (b) (pi/4+sqrt(2)-1) -pi/2 (c) (1-pi/4+sqrt(2))

The area of the region bounded by the curves y=x^(3),y=(1)/(x) between x=1 to x=2 is -