If matrix `A` is given by `A=|[6, 11], [2, 4]|` , then the determinant of `A^(2005)-6A^(2004)` is a. `2^(2006)` b. `(-11)2^(2005)` c. `-2^(2005)` d. `(-9)2^(2004)`

The digit in the unit place in the number (19)^(2005)+(11)^(2005)-(9)^(2005) is

The last digit of (1!+2!++2005 !)^(500) is (A) 9 (B) 2 (C) 7 (D) 1

Factorise : 4a^(2)+11a+6

If the determinant of the matrix [(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3))] is denoted by D, then the determinant of the matrix [(a_(1)+3b_(1)-4c_(1),b_(1),4c_(1)),(a_(2)+3b_(2)-4c_(2),b_(2),4c_(2)),(a_(3)+3b_(3)-4c_(3),b_(3),4c_(3))] will be -

Factorise : 4(x^(2)-2x)^(2)+11(x^(2)-2x)+6

If t_n denotes the nth term of the series 2+3+6+11+18+... then t_(50) a. 49^2-1 b. 49^2 c. 50^2+1 d. 49^2+2

If the matrix [(a,b),(c,d)] is commutative with the matrix [(1,1),(0,1)] then

If a ,b ,c in R^+ , then the minimum value of a(b^2+c^2)+b(c^2+a^2)+c(a^2+b^2) is equal to (a) a b c (b) 2a b c (c) 3a b c (d) 6a b c

If A={6,9,11}, B={}. Find A cup phi .