Reduce the line 2x-3y + 5 =0, in slope-intercept, intercept and normal forms. Also, find the distance of the line from origin and inclination of normal of the line with x-axis.

Find the slope of the lines : Making inclination of 60^(@) with the positive direction of x- axis.

Find the distance of the line 4x + 7y + 5 = 0 from the point (1, 2) along the line 2x - y = 0 .

On the portion of the line x+3y-3=0 which is intercepted between the coordinate axes,a square is constructed on the side of line away from the origin .Find co-ordinates of the intersection of its diagonals.Also find the equation of the opposite side of the given side.

The straight line 2x-3y+5=0 intersects the x -axis and y- axis-

The distance of the straight line a(x-a)+b(y-b)=0 from the origin is -

Find the distance of the point (3. 5) from the line 2x + 3y = 14measured parallel to th line x - 2y= 1,

Find the equation of the normal to the circle x^2+y^2-2x=0 parallel to the line x+2y=3.

The inclination of a straight line is 150^(@) , if the perpendicular distance of the line from the origin is 10 units , find the equation of the straight line .

The slope and y - intercept of the line 2x-3y +5=0 are -

Reduce the equation of the plane 4x+3y-6z-12=0 to intercept from and find its intercepts on the coordinate axis.