Find the values of non-negative real numbers `h_(1), h_(2), h_(3), k_(1), k_(2), k_(3)` such that algebraic sum of the perpendiculars drawn from points `(2, k_(1)),(3, k_(2)), (7, k_(3)), (h_(1), 4), (h_(2), 5), (h_(3),-3)` on a variable line passing through (2,1) is zero.

Find the values of non-negative real number h_1, h_2, h_3, k_1, k_2, k_3 such that the algebraic sum of the perpendiculars drawn from the points (2,k_1),(3,k_2),*7,k_3),(h_1,4),(h_2,5),(h_3,-3) on a variable line passing through (2, 1) is zero.

Find the value of k so that point colinear (7,-2), (5,1), (3,k).

Find the value of ‘K’ for which the points are collinear (7, -2) (5, 1) (3, K)

Find the value of ‘K’ for which the points are collinear (K, K) (2, 3) and (4, -1).

Why is K_(a_(2))ltltK_(a_(1)) for H_(2)SO_(4) in water?

If the length of the perpendicular drawn from (1,2,3) to the line (x-6)/(3)=(y-7)/(2)=(z-7)/(-2) is K units, then the value of K is -

The coordinates of the foot of the perpendicular drawn from the origin upon a line are (h,k) , show that the equation of the line is hx+ky=h^(2)+k^(2)(h^(2)+k^(2)ne0) .

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

If the points(-1,3), (2,h) and (5,-1) are collinear, then the value of h is

Let A_(1), A_(2), A_(3), A_(4) be the areas of the triangular faces of a tetrahedron, and h_(1), h_(2), h_(3), h_(4) be the corresponding altitudes of the tetrahedron. If the volume of tetrahedron is 1//6 cubic units, then find the minimum value of (A_(1) +A_(2) + A_(3) + A_(4))(h_(1)+ h_(2)+h_(3)+h_(4)) (in cubic units).