The diagonals of a parallelogram PQRS are along the lines x+3y =4 and 6x-2y = 7, Then PQRS must be :

Two sides of a parallelogram are along the lines x+y=3 and x=y+3. If its diagonals intersect at (2, 4) , then one of its vertices is

The lines 4x+4y =1,8x -3y =2 and y=0 are-

One diagonal of a square is along the line 8x-15 y=0 and one of its vertex is (1, 2). Then the equations of the sides of the square passing through this vertex are (a)23 x+7y=9,7x+23 y=53 (b)23 x-7y+9=0,7x+23 y+53=0 (c)23 x-7y-9=0,7x+23 y-53=0 (d)none of these

The angle between the lines -6x=y=4z and 2x=3y=-z is -

Find the angle between the lines 2x=3y=-z and 6x=-y=-4z

The equation of the diagonal, through the origin, of the quadrilateral formed by the lines x=0, y=0, x+y=1 and 6x+y=3 is given by

The orthocentre of the triangle formed by the lines x+y=1,2x+3y=6 and 4x-y+4=0 lies in

The equation of the diagonal of the square formed by the pairs of lines xy +4x - 3y - 12 = 0 and xy - 3x +4 y - 12 = 0 is

Two sides of a rhombus are along the lines x - y + 1 = 0 and 7 x - y - 5 = 0 . If its diagonals intersect at ( - 1, -2) , then which one of the following is a vertex of this rhombus ?

The equation of the two adjacent sides of a parallelogram are 4x+ 5y = 0 and 7x + 2y =.0and equation of one of the diagonal is 1 lx + 7y = 9, find the equation of other diagonal.