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The line x+y=p meets the x- and y-axes ...

The line `x+y=p` meets the x- and y-axes at `Aa n dB` , respectively. A triangle `A P Q` is inscribed in triangle `O A B ,O` being the origin, with right angle at `QdotP` and `Q` lie, respectively, on `O Ba n dA B` . If the area of triangle `A P Q` is `3/8t h` of the are of triangle `O A B ,` the `(A Q)/(B Q)` is equal to (a)`2 `(b) `2/3` (c) `1/3` (d)` 3`

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