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A beam of light is sent along the line x...

A beam of light is sent along the line `x-y=1` , which after refracting from the x-axis enters the opposite side by turning through `30^0` towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) `(2-sqrt(3))x-y=2+sqrt(3)` (b)`(2+sqrt(3))x-y=2+sqrt(3)` (c)`(2-sqrt(3))x+y=(2+sqrt(3))` (d)`y=(2-sqrt(3))(x-1)`

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