The probability that a marksman will hit a target is given is 1/5. Then the probability that at least once hit in 10 shots is `1-(4//5)^(10)` b. `1//5^(10)` c. `1-(1//5)^(10)` d. `(4//5)^(10)`

The probability that a student is not a swimmer is 1/5 . Then the probability that out of five students, four are swimmers is (A) ^5C_4""(4/5)^4""1/5 (B) (4/5)^4""1/5 (C) ^5C_1 1/5(4/5)^4 (D) None of these

The probability that A hits a target is 1/3 and the probability that B hits it is 2/5 . What is the probability that the target will be hit if both A and B shoot at it?

The probability of a man hitting a target is (1)/(4) . How many times must he fire so that the probability of his hitting the target at least once is greater than (2)/(3) ?

Probability that A speaks truth is 4/5 . A coin is tossed. A reports that a head appears. The probability that actually there was head is (A) 4/5 (B) 1/2 (C) 1/5 (D) 2/5

The probability that a bulb produced by a factory will fuse after 150 days if used is 0.05. what is the probability that out of 5 such bulbs none will fuse after 150 days of use? 1-(19/20)^5 b. (19/20)^5 c. (3/4)^5 d. 90(1/4)^5

The probability of hitting a target by three marksmen are 1/2, 1/3 and 1/4. Then find the probability that no one will hit the target when they fire simultaneously.

A die is thrown 31 times. The probability of getting 2,4 or 5 at most 15 times is (a) (1)/(3) (b) (1)/(4) (c) (1)/(5) (d) (1)/(2)

A bag contains 20 coins. If the probability that the bag contains exactly 4 biased coin is 1/3 and that of exactly 5 biased coin is 2/3 , then the probability that all the biased coin are sorted out from bag is exactly 10 draws is a. 5/(10)(.^(16)C_6)/(.^(20)C_9)+1/(11)(.^(15)C_5)/(.^(20)C_9) b. 2/(33)[(.^(16)C_6+5 .^(15)C_5)/(.^(20)C_9)] c. 5/(33)(.^(16)C_7)/(.^(20)C_9)+1/(11)(.^(15)C_6)/(.^(20)C_9) d. none of these

A can hit a target in 3 out of 4 shots and B can hit the target in 4 out of 5 shots. What is the probability of hitting the target ?

The probability of hitting a target by three marksmen are 1/2, 1/3 and 1/4. Then find the probability that one and only one of them will hit the target when they fire simultaneously.