`Ea n dF` are two independent events. The probability that both `Ea n dF` happen is 1/12 and the probability that neither `Ea n dF` happens is 1/2. Then, `A) P(E)=1//3, P(F)=1//4` `B) P(E)=1//4, P(F)=1//3` `C) P(E)=1//6, P(F)=1//2` `D) P(E)=1//2, P(F)=1//6`

If Aa n dB are two independent events such that P(A)=1//2 a n d P(B)=1//5, then

Let E and F be two independent events. The probability that exactly one of them occurs is 11/25 and the probability if none of them occurring is 2/25 . If P(T) denotes the probability of occurrence of the event T , then (a) P(E)=4/5,P(F)=3/5 (b) P(E)=1/5,P(F)=2/5 (c) P(E)=2/5,P(F)=1/5 (d) P(E)=3/5,P(F)=4/5

A and B are two independent events such that P(A cap B) =(1)/(12) and P (either A or B) =(1)/(2) , then -

If P(A) = 1/3 , P(B) = 1/2, P(AIB) = 1/6 . find P(BIA) .

If A and B are two independent events such that P( barA nnB)=2//15 and P(Ann barB )=1//6 , then P(B) is

If A and B are two independent events such that P (A) = 1//2, P(B)=1//5, then find P(AuuB) and P(A|B)

A and B are two independent event. It P(A) = 1/2 and P(A cup B) =2/3,find the value of P(B).

A and B are two independent events P(A) = 1/3 and P(A nnB) = 1/6 , then P(A^C nn B^C) will be

If p be occurrence of an event in a single trail, then show that the probability of at least one occurrence in n trials is 1-(1-p)^n .

A and B are two independent events such that P(A)=(1)/(2) and P(B)=(1)/(3) . Then the value of P(A^(c ) cap B^(c )) is -