Let `0ltP(A)lt1, 0ltP(B)lt1 and P(AcupB)=P(A)+P(B)-P(A)P(B),` then,

Let A and B be two events such that P(A) =1/3,P(B)=1/4 and P(AnnB)=1/4 . Find P(A//B),P(B//A),P(AuuB) .

A and B are events of an experiment such that 0 lt P(A) , P(B) lt 1 . If P(B') gt P(A') , then

Let A and B be events with P(A)=3/8,P(B)=5/8 and P(AcupB)=3/4 then P(A/B) =

Let A and B be events with P(A)=3/8,P(B)=5/8 and P(AcupB)=3/4 then P(AcapB) =

If A and B are arbitrary events, then a) P(A nn B) ge P(A)+ P(B) (b) P(A nn B) le P(A)+ P(B) (c) P(AnnB)=P(A)+ P(B) (d)None of these

Two events A and B are such that P(A)=(1)/(4), P(B//A)=(1)/(2) and P(A//B)=(1)/(4) , then the value of P(A^(c )//B^(c )) is -

If A and B are two events such that P(A) =(1)/(4), P(B) = (1)/(2) and P(A cap B) = (1)/(8) , find P (not A and not B).

Show that P(B)>0 , then P(A_1 cup A_2|B) = P(A_1|B) + P(A_2|B)-P(A_1 cap A_2|B) .

For any two events A and B, show that max {P(A),P(B)} le P(A cup B) le min{P(A) + P(B),1} Where A cup B, A cap B, max{P(A), P(B)} and min {P(A)+P(B),1} are the occurence of A and B, occurence of A and B both, maximum of P(A) and P(B): minimum of P(A) + P(B) and 1 respectively.

Statement-I : If (1)/(5)(1+5p), (1)/(3)(1+2p), (1)/(3)(1-p) and (1)/(5)(1-3p) are probabilities of four mutually exclusive events, then p can take infinite number of values. Statement-II : If A, B, C and D are four mutually exclusive events, then P(A), P(B), P(C ), P(D) ge 0 and P(A) +P(B)+P(C )+P(D ) le 1.