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Statement 1: If P(A)=0. 25 ,P(B)=0. 50 ,...

Statement 1: If `P(A)=0. 25 ,P(B)=0. 50 ,a n dP(AnnB)=0. 14` , then the probability that neither A nor B occurs is 0.39. Statement 2: `P( barA nn barB )= 1-P(A uu B)`

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Each of the following question contain two statements- Statemnet I and statement II. Each of the questions has following four choice A,B,C and D only one of which is correct. Statement - I P(A) = 0.25, P(B) = 0.50 and P(AcapB) = 0.14 , then the probability that neither A nor B occurs is 0.39. Statement - II: P(bar(AcupB)) = bar(A)cup bar(B)

If P (A) = 0. 8 ,and P(B|A) = 0. 4 , find P(AnnB)

if P(A|B) = 1/3 , P(A) = 1/4 and P(B) = 1/2, find the probability that exactly one of the events A and B occurs.

If P(A) = 0.2, P(B) = 0.4, P(AB) = 0.08, then P(B/A^c) equals to

If P(A) = 0.8, P(B) = 0.5 and P (B|A) = 0.4, find P(A|B)

If P(A)=0.54, P(B)=0.69 and P(A cap B)=0.35 , then the value of P(A' cup B') is-

If P(A) = 0.8, P(B) = 0.5 and P (B|A) = 0.4, find P(A cap B)

If P(A) = 0.8, P(B) = 0.5 and P (B|A) = 0.4, find P(A cup B) 

If P(A)=2/3,P(B)=1/2 and P(AnnB)=1/6 then find the value of P(AnnB^C) .

If P(A//B)= 0.75, P(B//A) = 0.6 and P(A)=0.4 find the value of P(barA//barB)

CENGAGE PUBLICATION-PROBABILITY-All Questions
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  2. Let 0ltP(A)lt1, 0ltP(B)lt1 and P(AcupB)=P(A)+P(B)-P(A)P(B), then,

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