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A bag contains 20 coins. If the probabil...

A bag contains 20 coins. If the probability that the bag contains exactly 4 biased coin is `1/3` and that of exactly 5 biased coin is `2/3`, then the probability that all the biased coin are sorted out from bag is exactly 10 draws is
a. `5/(10)(.^(16)C_6)/(.^(20)C_9)+1/(11)(.^(15)C_5)/(.^(20)C_9)`
b. `2/(33)[(.^(16)C_6+5 .^(15)C_5)/(.^(20)C_9)]`
c. `5/(33)(.^(16)C_7)/(.^(20)C_9)+1/(11)(.^(15)C_6)/(.^(20)C_9)`
d. none of these

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