A coin is tossed `2n` times. The chance that the number of times one gets head is not equal to the number of times one gets tails is `((2n !))/((n !)^2)(1/2)^(2n)` b. `1-((2n !))/((n !)^2)` c. `1-((2n !))/((n !)^2)1/(4^n)^` d. none of these

A fair coin is tossed 2n times. The change that number of times one gets head is not equal to the number of times one gets tail is

A coin is tossed 2n times. The probability of getting head n times, is -

The total number of ways in which 2n persons can be divided into n couples is a. (2n !)/(n ! n !) b. (2n !)/((2!)^3) c. (2n !)/(n !(2!)^n) d. none of these

A coin is tossed n times. The probability of getting head at least once is more than 0.8 , then the value of n is

A coin is tossed (m + n) times (m gtn). Show that the probability of at least m consecutive heads is (n+2)//2^(m+2).

The coefficient of 1//x in the expansion of (1+x)^n(1+1//x)^n is (a). (n !)/((n-1)!(n+1)!) (b). ((2n)!)/((n-1)!(n+1)!) (c). ((2n)!)/((2n-1)!(2n+1)!) (d). none of these

The number of distinct terms in the expansion of is (x^(3)+(1)/(x^(3))+1)^(n) is (a) 2n (b) 3n (c) 2n+1 (d) 3n+1

In a game a coin is tossed 2n+m times and a player wins if he does not get any two consecutive outcomes same for at least 2n times in a row. The probability that player wins the game is a. (m+2)/(2^(2n)+1) b. (2n+2)/(2^(2n)) c. (2n+2)/(2^(2n+1)) d. (m+2)/(2^(2n))

In a sequence of (4n+1) terms, the first (2n+1) terms are n A.P. whose common difference is 2, and the last (2n+1) terms are in G.P. whose common ratio is 0.5 if the middle terms of the A.P. and LG.P. are equal ,then the middle terms of the sequence is (n .2 n+1)/(2^(2n)-1) b. (n .2 n+1)/(2^n-1) c. n .2^n d. none of these

Answer the following questions: Two persons toss a fair coin n times each. Show that the probability of their scoring same no. of tails is ((2n)/n).(2^(-2n)) .