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Area of the triangle formed by the line ...

Area of the triangle formed by the line `x+y=3` and angle bisectors of the pair of straight lines `x^2-y^2+2y=1` is
a.`2s qdotu n i t s`
b. `4s qdotu n i t s`
c. `6s qdotu n i t s`
d. `8s qdotu n i t s`

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The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is (a) 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

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The area of the region containing the points (x , y) satisfying 4lt=x^2+y^2lt=2(|x|+|y|) is (a) 8s qdotu n i t s (b) 2s qdotu n i t s (c) 4pis qdotu n i t s (d) 2pis qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

Let f(x)=x^3+3x+2 and g(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is (a) 9/2s qdotu n i t s (b) 4/3s qdotu n i t s (c) 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

Consider two curves C_1: y^2=4[sqrt(y)]x a n dC_2: x^2=4[sqrt(x)]y , where [.] denotes the greatest integer function. Then the area of region enclosed by these two curves within the square formed by the lines x=1,y=1,x=4,y=4 is (a) 8/3s qdotu n i t s (b) (10)/3s qdotu n i t s (c) (11)/3s qdotu n i t s (d) (11)/4s qdotu n i t s

The area of the smaller region bounded by circle x^2+y^2=1 and |y|=x+1 (a) pi/2-1/2s qdotu n i t s (b) pi/2-1s qdotu n i t s (c) pi/2s qdotu n i t s (d) pi/2 +1s qdotu n i t s

The area bounded by the curve a^2y=x^2(x+a) and the x-axis is (a^2)/3s qdotu n i t s (b) (a^2)/4s qdotu n i t s (3a^2)/4s qdotu n i t s (d) (a^2)/(12)s qdotu n i t s

The graph of y^2+2x y+40|x|=400 divides the plane into regions. Then the area of the bounded region is (a) 200s qdotu n i t s (b) 400s qdotu n i t s (c) 800s qdotu n i t s (d) 500s qdotu n i t s

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