Let `P` be a point on the circle `x^2+y^2=9,Q` a point on the line `7x+y+3=0` , and the perpendicular bisector of `P Q` be the line `x-y+1=0` . Then the coordinates of `P` are (a) `(0,-3)` (b) `(0,3)` `((72)/(25),(21)/(35))` (d) `(-(72)/(25),(21)/(25))`

P is a point on the straight line 7x-4y-29=0 . If the foot of the perpendicular drawn from P on the line 5x+2y+18=0 be N(-2,-4) , find the coordinates of P.

Find the point on the curve 3x^2-4y^2=72 which is nearest to the line 3x+2y+1=0.

If the perpendicular distance from origin to the straight line 4x-3y+P=0 is 2 unit,then the value of P is

The line joining the points A(2,1) and B(3,2) is perpendicular to the line (a^2)x+(a+2)y+2=0. Find the values of a .

The image of P(a,b) on the line y=-x is Q and the image of Q on the line y=x is R find the mid-point of P and R

Find the distance between A(2,3) on the line of gradient 3/4 and the point of intersection P of this line with 5x+7y+40=0.

If a , b and c are in A P , then the straight line a x+b y+c=0 will always pass through a fixed point whose coordinates are (a) (1,2) (b) (1,-2) (c) (2,3) (d) (0,0)

The coordinates of the foot of the perpendicular from the point (2,3) on the line -y+3x+4=0 are given by

P is a point on the line y+2x=1, and Qa n dR two points on the line 3y+6x=6 such that triangle P Q R is an equilateral triangle. The length of the side of the triangle is

Let P=0 be the equation of a plane passing through the line of intersection of the planes 2x-y=0a n d3z-y=0 and perpendicular to the plane 4x+5y-3z=8. Then the points which lie on the plane P=0 is/are a. (0,9,17) b. (1//7,21//9) c. (1,3,-4) d. (1//2,1,1//3)