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If C1: x^2+y^2=(3+2sqrt(2))^2 is a circl...

If `C_1: x^2+y^2=(3+2sqrt(2))^2` is a circle and `P A` and `P B` are a pair of tangents on `C_1,` where `P` is any point on the director circle of `C_1,` then the radius of the smallest circle which touches `c_1` externally and also the two tangents `P A` and `P B` is
(a) `2sqrt(3)-3` (b) `2sqrt(2)-1` (c) `2sqrt(2)-1` (d) 1

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