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Prove that [ vec l vec m vec n][ vec a v...

Prove that `[ vec l vec m vec n][ vec a vec b vec c]=| (vec l. vec a, vec l. vec b, vec l.vec c), (vec m. vec a, vec m. vec b, vec m.vec c),( vec n. vec a, vec n. vec b, vec n.vec c)|` .

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If vec axx( vec bxx vec c) is perpendicular to ( vec axx vec b)xx vec c , we may have a. ( vec a. vec c)| vec b|^2=( vec a. vec b)( vec b.vec c)( vec c.vec a) b. vec adot vec b=0 c. vec adot vec c=0 d. vec bdot vec c=0

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