The parabola `y^2=4x` and the circle having its center at (6, 5) intersect at right angle. Then find the possible points of intersection of these curves.

Find the maximum number of points of intersection of 6 circles.

find the angle of intersection of the curve xy=6 and x^2y=12

The ellipse 4x^2+9y^2=36 and the hyperbola a^2x^2-y^2=4 intersect at right angles. Then the equation of the circle through the points of intersection of two conics is (a) x^2+y^2=5 (b) sqrt(5)(x^2+y^2)-3x-4y=0 (c) sqrt(5)(x^2+y^2)+3x+4y=0 (d) x^2+y^2=25

Find the angle of intersection of the curves x y=a^2a n dx^2-y^2=2a^2

The curve be y=x^2 whose slopeof tangent is x, so find the point of intersection of the tangent and the curve.

Tangents are drawn to the parabola y^2=4a x at the point where the line l x+m y+n=0 meets this parabola. Find the point of intersection of these tangents.

If line x-2y-1=0 intersects parabola y^(2)=4x at P and Q, then find the point of intersection of normals at P and Q.

If the tangents are drawn to the circle x^2+y^2=12 at the point where it meets the circle x^2+y^2-5x+3y-2=0, then find the point of intersection of these tangents.

Two congruent circles with centered at (2, 3) and (5, 6) which intersect at right angles, have radius equal to (a) 2 sqrt(3) (b) 3 (c) 4 (d) none of these