Find the foci of the ellipse `25(x+1)^2+9(y+2)^2=225.`

Prove that the 4 foci of the two ellipses 25x^2+169y^2=4225 and 400x^2+256y^2=102400 are concyclics.

The coordinates of the foci of the ellipse 20x^2+4y^2=5 are

Find the distance between the foci of the ellipse 3x^(2) + 4y^(2) = 12 .

The foci of a hyperbola coincide with the foci of the ellipse x^2/25 +y^2/9 =1 . Find the equation of the hyperbola if its eccentricity is 2.

Find the length of latus rectum and the coordinates of the foci of the ellipse 25x^(2) + 4y^(2) = 100 .

If the foci of the ellipse (x^2)/(16)+(y^2)/(b^2)=1 and the hyperbola (x^2)/(144)-(y^2)/(81)=1/(25) coincide, then find the value of b^2

If a hyperbola passes through the foci of the ellipse (x^2)/(25)+(y^2)/(16)=1 . Its transverse and conjugate axes coincide respectively with the major and minor axes of the ellipse and if the product of eccentricities of hyperbola and ellipse is 1 then the equation of a. hyperbola is (x^2)/9-(y^2)/(16)=1 b. the equation of hyperbola is (x^2)/9-(y^2)/(25)=1 c. focus of hyperbola is (5, 0) d. focus of hyperbola is (5sqrt(3),0)

Find the coordinates of foci of the ellipse 5 x^(2) + 9y ^(2) - 10x + 90 y + 185 = 0

The length of latus rectum of the ellipse 25x^(2) + 9y ^(2) = 225 is _