Let `y=x^(3)-8x+7 and x=f(t)." If "(dy)/(dt)=2 and x=3 at t = 0," `then
` "(dx)/(dt)` at t = 0 is given by`

Let y=x^(3)-8x+7 and x=f(t) given t=0, x=3 Find the value of (dy)/(dx)

dx/dt + x cos t = 1/2 sin 2 t

Find (dy)/(dx) if:- x = 2t,y= t^3

If f(x)=int_0^x(sint)/t dt ,x >0, then

If f(t) is an odd function, then int_(0)^(x)f(t) dt is -

If int_(0)^(x)f(t)dt=x^2+int_(x)^(1)t^2f(t)dt , then f((1)/(2)) is equal to

If y=int_(x^(2))^(x^(3))1/(logt)dt(xgt0) , then find (dy)/(dx)

If y(t) is a solution of (1+t)dy/dt-t y=1 and y(0)=-1 then y(1) is

If y=int_(0)^(x)(t-1)(t-2)^(2)dt , find x for which (dy)/(dx)=0 .

The second derivative of a single valued function parametrically represented by x=varphi(t)a n dy=psi(t) (where varphi(t)a n dpsi(t) are different function and varphi^(prime)(t)!=0 ) is given by (d^2y)/(dx^2)=(((dx)/(dt))((d^2y)/(dt^2))-((d^2x)/(dt^2))((dy)/(dt))/(((dx)/(dt))^2) (d^2y)/(dx^2)=(((dx)/(dt))((d^2y)/(dt^2))-((d^2x)/(dt^2))((dy)/(dt))/(((dx)/(dt))^3) (d^2y)/(dx^2)=(((d^2x)/(dt))((d^y)/(dt^2))-((d^x)/(dt^))((d^2y)/(dt^2))/(((dx)/(dt))^3) (d^2y)/(dx^2)=(((d^2x)/(dt^2))((d^y)/(dt^))-((d^2x)/(dt^2))((d^y)/(dt^))/(((dx)/(dt))^3)