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Let f(x)=(g(x))/x when x!=0 and f(0)=0....

Let `f(x)=(g(x))/x ` when `x!=0` and `f(0)=0.` If `g(0)=g^(prime)(0)=0`and
`g^`"`(0)=17` then `f^(prime)(0)=` a).`3/4` b). `-1/2` c). `17/3` d). `17/2`

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