Three balls marked with 1, 2 and 3 are placed in an urn. One ball is drawn, its number is noted, then the ball is returned to the urn. This process is repeated and then repeated once more. Each ball is equally likely to be drawn on each occasion. If the sum of the number noted is 6, then the probability that the ball numbered with 2 is drawn at all the three occassion, is

Options

A. `(1)/(27)`
B. `(1)/(7)`
C. `(1)/(6)`
D. `(1)/(3)`

Answer

B

Explanation

Since the sum of the noted numbers is 6, the number on the balls are either 1, 2, 3 or 2, 2, 2.
So, total number of cases = `3! + = 7`
So, the required probability = `1//7`