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Seven girls G(1), G(2), G(3), …, G(7) ar...

Seven girls `G_(1), G_(2), G_(3)`, …, `G_(7)` are such that their ages are in order `G_(1) lt G_(2) lt G_(3) lt … lt G_(7)`. Five girls are selected at random and arranged in increasing order of their ages. The probability that `G_(5)` and `G_(7)` are not consecutive is

A

`(20)/(21)`

B

`(19)/(21)`

C

`(17)/(21)`

D

`(13)/(21)`

Text Solution

Verified by Experts

The correct Answer is:
C

Required probability = 1 - P (`G_(5)` and `G_(7)` are consecutive)
`= 1 - (.^(4)C_(3))/(.^(7)C_(5)) = (17)/(21)`
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