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Show that (p^^q)vv(~p)vv(p^^~q) is a tau...

Show that `(p^^q)vv(~p)vv(p^^~q)` is a tautology

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fol all possible truth values of p and q, the compound statement
`(p^^q)vv(~p)vv(p^^~q)` is true.
Thus, `(p^^q) vv(~p)vv(p^^~q)` is a tautology .
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