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If mu is the mean of a distribution , th...

If `mu` is the mean of a distribution , then `sumf_i(y_i-mu)` is equal to

A

M.D.

B

S.D.

C

0

D

Relative frequency

Text Solution

Verified by Experts

The correct Answer is:
C
We have,
`sumf_(i)(y_(i)-mu)=sum f_(i)y_(i)-mu sum f_(i)=mu sum f_(i)-mu sum f_(i)=0 " " [because mu=(sum f_(i)y_(i))/(sum f_(i))]`
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