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Area of the triangle formed by the line ...

Area of the triangle formed by the line `x+y=3` and the angle bisectors of the pairs of straight lines `x^2-y^2+2y=1` is (a) `2` sq units (b) `4` sq units (c) `6` sq units (d) `8` sq units

A

2 sq . Units

B

4 sq . Units

C

6 sq. units

D

8 sq. units

Text Solution

Verified by Experts

The correct Answer is:
1
`x^(2)-y^(2)+2y=1orx=+-(y-1)`

The bisectors of the above lines are `x=0 and y=1`.

So , the area between `x=0,y=1, and x+y=3` is the shaded region shown in the figure . The area is given by `(1//2)xx2xx2=2` sq. units.
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